3x^2-18x+33=6

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Solution for 3x^2-18x+33=6 equation: 



3x^2-18x+33=6

We move all terms to the left:

3x^2-18x+33-(6)=0

We add all the numbers together, and all the variables

3x^2-18x+27=0

a = 3; b = -18; c = +27;
Δ = b2-4ac
Δ = -182-4·3·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{18}{6}=3$

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